1828 Presidential Election Results
Andrew Jackson (Democratic) won the 1828 presidential election with 178 of 261 electoral votes, defeating John Quincy Adams (National Republican, 83). Jackson also won the popular vote with 56.2%.
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Results by state
| State | EV | Jackson | Adams | Votes cast |
|---|---|---|---|---|
| Alabama | 5 | 89.9%16,7365 EV | 10.1%1,878 | 18,614 |
| Connecticut | 8 | 24.3%4,448 | 75.7%13,8298 EV | 18,277 |
| Delaware | 3 | – | 3 EV | — |
| Georgia | 9 | 96.8%19,3629 EV | 3.2%642 | 20,004 |
| Illinois | 3 | 67.2%9,5603 EV | 32.8%4,662 | 14,222 |
| Indiana | 5 | 56.6%22,2015 EV | 43.4%17,009 | 39,210 |
| Kentucky | 14 | 55.5%39,30814 EV | 44.5%31,468 | 70,776 |
| Louisiana | 5 | 53.0%4,6055 EV | 47.0%4,082 | 8,687 |
| Massachusetts | 15 | 16.8%6,012 | 83.2%29,83615 EV | 35,848 |
| Maryland | 11 | 49.8%22,7825 EV | 50.3%23,0146 EV | 45,796 |
| Maine | 9 | 40.1%13,9271 EV | 59.9%20,7738 EV | 34,700 |
| Missouri | 3 | 70.6%8,2323 EV | 29.4%3,422 | 11,654 |
| Mississippi | 3 | 81.1%6,7633 EV | 19.0%1,581 | 8,344 |
| North Carolina | 15 | 73.1%37,81415 EV | 26.9%13,918 | 51,732 |
| New Hampshire | 8 | 45.9%20,212 | 54.1%23,8238 EV | 44,035 |
| New Jersey | 8 | 47.9%21,809 | 52.1%23,7538 EV | 45,562 |
| New York | 36 | 51.5%139,41220 EV | 48.6%131,56316 EV | 270,975 |
| Ohio | 16 | 51.6%67,59616 EV | 48.4%63,453 | 131,049 |
| Pennsylvania | 28 | 66.7%101,45728 EV | 33.4%50,763 | 152,220 |
| Rhode Island | 4 | 22.9%820 | 77.1%2,7554 EV | 3,575 |
| South Carolina | 11 | 11 EV | – | — |
| Tennessee | 11 | 95.2%44,29311 EV | 4.8%2,240 | 46,533 |
| Virginia | 24 | 69.0%26,85424 EV | 31.0%12,070 | 38,924 |
| Vermont | 7 | 25.5%8,350 | 74.5%24,3637 EV | 32,713 |
Popular vote shares are of the votes for the candidates listed in the source. A dash under Votes cast means the state legislature chose the electors. Sources: the National Archives (electoral votes), the American Presidency Project and the Clerk of the House (popular vote).